OK ... This is absolutely driving me nuts here. Hopefully, any of you skilled machinists can tell me what is going on.
I set up my milling vise and tram it to less than 0.001". I am using a Kurtz clone here.
I then find the edge using an edge finder on the stationary part of the vise. and find the edge and hit the ZERO on my DRO.
I then put a precision parallel in the vise so I can find the very same edge ... but going in the exact opposite direction.
I get a a very consistent offset of 0.005"!
Now ... I have fully checked out the DRO using a dial indicator, and I get a hysteresis of 0.001". This is to be expected because the DRO (Accuremote), is specified to 0.0005". Knowing about encoders, I fully expect a forward and back hysteresis of 0.001"
What is driving me nuts is the 0.005" hysteresis using an edge finder. I am not using one of those wigglers. I am using one of those edge finders that is chucked up using a 3/8" collet and has a 0.200" diameter pin.
Can anyone tell me what is going on? Now, I have no idea about where the true edge is when I do this operation.
Thanks;
Ken
I set up my milling vise and tram it to less than 0.001". I am using a Kurtz clone here.
I then find the edge using an edge finder on the stationary part of the vise. and find the edge and hit the ZERO on my DRO.
I then put a precision parallel in the vise so I can find the very same edge ... but going in the exact opposite direction.
I get a a very consistent offset of 0.005"!
Now ... I have fully checked out the DRO using a dial indicator, and I get a hysteresis of 0.001". This is to be expected because the DRO (Accuremote), is specified to 0.0005". Knowing about encoders, I fully expect a forward and back hysteresis of 0.001"
What is driving me nuts is the 0.005" hysteresis using an edge finder. I am not using one of those wigglers. I am using one of those edge finders that is chucked up using a 3/8" collet and has a 0.200" diameter pin.
Can anyone tell me what is going on? Now, I have no idea about where the true edge is when I do this operation.
Thanks;
Ken



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