Ring height for vortex diamondback

[shin_en]

So I was reading the $150 scope review thread and decided in getting the vortex diamondback 4-12x40 for my newly acquired rem 700sps. I've decided on a seekins 20moa base and looking into the seekins scope rings but they only come in a low height.

My question is would the low height rings be ok or would it be too low?

I'm new to scopes and ring heights and all that

Thanks

[ExtremeX]

I have a Vortex Diamondback 3-9x40 and used Leupold PRW Low rings for a 1" tube. I think the website says the low are 0.8" high.

If you use medium on the SPS Tactical you may need a cheek riser. I did when I upgraded my scope but the new one has a 50mm objective and I use medium rings.

[shin_en]

i'm not sure if this is correct but here is my math (going by logic)...

so the seekins low rings are .76" high. since the tube is 1" i'll take half of that and add it to the .76" giving me 1.26" of height from the middle of the scope to the bottom of the rail. if i follow this logic then i just need the radius of the objective to be less than 1.26". if the redius of the objective is 20mm this comes out to .787" so in theory i'd have about .5" of room left...?

also if i'm only just starting out with long range shooting should i go with a 20moa base or a 0 moa base as most of my shooting now will be about 100yrds. the moa of the vortex diamondback is 60moa.

edit: i just saw that the .76" is from rail top to ring center. i forgot to add in the scope base which is .29" giving me 1.05" which means i'm ok?

[NiteQwill]

You must measure them yourself or get the dimensions. By my calculations, the scope should fit.

This is using a 20 MOA Seekins Precision base (which I believe has a 9.81 mm thickness, AFAIK). I use a Seekins 0 MOA base since there is tons of elevations in "most" scopes I've encountered.

Now using math:

Rings + Base (9.81 mm) = Total height

Using a conservative value of 5 mm thickness added to the objective lens diameter from the Butler Creek Covers, I get this value:

[40 mm + 5 mm] / 0.5 = 22.5 mm

Finally, using this formula and solving for rings:

[Rings + 9.81 mm] - 22.5 = 0.128 mm (thickness of a $1 bill)

Ring height should be great than or equal to 12.818 mm or 0.505 inches.

Low Seekins rings are .75 inches or 19.05 mm.

Hope this helps.

*I can't guarantee my math calculations... make sure to do your own*

[NiteQwill]

Actually, my calculations are off a little... the 40 mm objective should generally have an overall diameter close to 50 mm.

So, ring height must be 17.818 mm or greater. Even at dollar bill thickness (which is what most LR shooters look for), 1.232 mm tolerance can be cutting it close with 19.05 mm ring height.

YMMV.